n-[1-[n-(1-n)-1]]=0

Solution for n-[1-[n-(1-n)-1]]=0 equation:

Simplifying
n + -1[1 + -1[n + -1(1 + -1n) + -1]] = 0
n + -1[1 + -1[n + (1 * -1 + -1n * -1) + -1]] = 0
n + -1[1 + -1[n + (-1 + 1n) + -1]] = 0

Reorder the terms:
n + -1[1 + -1[-1 + -1 + n + 1n]] = 0

Combine like terms: -1 + -1 = -2
n + -1[1 + -1[-2 + n + 1n]] = 0

Combine like terms: n + 1n = 2n
n + -1[1 + -1[-2 + 2n]] = 0
n + -1[1 + [-2 * -1 + 2n * -1]] = 0
n + -1[1 + [2 + -2n]] = 0

Combine like terms: 1 + 2 = 3
n + -1[3 + -2n] = 0
n + [3 * -1 + -2n * -1] = 0
n + [-3 + 2n] = 0

Reorder the terms:
-3 + n + 2n = 0

Combine like terms: n + 2n = 3n
-3 + 3n = 0

Solving
-3 + 3n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 3n = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 3n = 0 + 3
3n = 0 + 3

Combine like terms: 0 + 3 = 3
3n = 3

Divide each side by '3'.
n = 1

Simplifying
n = 1